Discuz!系统的_xss_check()函数原本的意义是为了论坛安全,防止XSS攻击,一般网站使用是不会出现什么问题的,但是有些网站要接入第三方接口,当第三方接口向本站post数据的时候就会报"您当前的访问请求当中含有非法字符,已经被系统拒绝",本文介绍一种简单的修改方法避免此错误。
解决方案如下:
Code:
private function _xss_check() {

	static $check = array('"', '>', '<', '\'', '(', ')', 'CONTENT-TRANSFER-ENCODING');

	if(isset($_GET['formhash']) && $_GET['formhash'] !== formhash()) {

			system_error('request_tainting');

	}

	if($_SERVER['REQUEST_METHOD'] == 'GET' ) {

			$temp = $_SERVER['REQUEST_URI'];

	} elseif(empty ($_GET['formhash'])) {

			$temp = $_SERVER['REQUEST_URI'].file_get_contents('php://input');

	} else {

			$temp = '';

	}

	if(!empty($temp)) {

		$temp = strtoupper(urldecode(urldecode($temp)));

		foreach ($check as $str) {

				if(strpos($temp, $str) !== false) {

						system_error('request_tainting');

				}

		}

	}

	return true;

}
替换为:

Code:
private function _xss_check() {

	$temp = strtoupper(urldecode(urldecode($_SERVER['REQUEST_URI'])));

	if(strpos($temp, '<') !== false || strpos($temp, '"') !== false || strpos($temp, 'CONTENT-TRANSFER-ENCODING') !== false) {

			system_error('request_tainting');

	}

	return true;

}